谁说desmos只能画二维图像

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函数表达式在此
(((-u * (cos(i) * sin(j)) +v * (cos(h) * cos(j) - sin(h) * sin(i) * sin(j)) +w* (sin(h) * cos(j) + cos(h) * sin(i) * sin(j)))- (-d * (cos(i) * sin(j)) +e * (cos(h) * cos(j) - sin(h) * sin(i) * sin(j)) +f* (sin(h) * cos(j) + cos(h) * sin(i) * sin(j))))/((d* (cos(i) * cos(j)) + e * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +f* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i)))(-u * (cos(i) * sin(j)) +v * (cos(h) * cos(j) - sin(h) * sin(i) * sin(j)) +w* (sin(h) * cos(j) + cos(h) * sin(i) * sin(j)))-(u* (cos(i) * cos(j)) + v * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +w* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i))) (-d * (cos(i) * sin(j)) +e * (cos(h) * cos(j) - sin(h) * sin(i) * sin(j)) +f* (sin(h) * cos(j) + cos(h) * sin(i) * sin(j)))))x+(((u* (cos(i) * cos(j)) + v * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +w* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i)))-(d* (cos(i) * cos(j)) + e * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +f* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i))))/((u* (cos(i) * cos(j)) + v * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +w* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i))) (-d * (cos(i) * sin(j)) +e * (cos(h) * cos(j) - sin(h) * sin(i) * sin(j)) +f* (sin(h) * cos(j) + cos(h) * sin(i) * sin(j)))-(d* (cos(i) * cos(j)) + e * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +f* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i)))(-u * (cos(i) * sin(j)) +v * (cos(h) * cos(j) - sin(h) * sin(i) * sin(j)) +w* (sin(h) * cos(j) + cos(h) * sin(i) * sin(j)))))y=1
定义域
(x-(u* (cos(i) * cos(j)) + v * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +w* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i))))(x-(d* (cos(i) * cos(j)) + e * (cos(h) * sin(j) + sin(h) * sin(i) * cos(j)) +f* (sin(h) * sin(j) - cos(h) * sin(i) * cos(i))))<=0
其中h,i,j分别是三个旋转角度，(u,v,w)(d,e,f)是每一条棱的顶点坐标